Question: #1533
Week 5 Final Exam Complete Solution Answers
| $1,000(1+0.02)^5 = 1104 | |
| FV=R/i*[(1+i)^n-1]=2500/0.05*(1.05^5-1)=13814.08 | |
| R=PV*i/(1-1/(1+i)^n)=2000*0.06/(1-1/1.06^3)=748.22, 748.22*3=2244.66 | |
| collection=0.1*15000+0.2*25000+0.7*10000=13500 | |
| inventory turnover=cost of goods sale/average inventory=219793/29447=7.46, days of inventory on hand=365/inventory turnover=48.9 | |
| inventory turnover=cost of goods sale/average inventory=219793/29447=7.46??? | |
Solution: #1515
Week 5 Final Exam Complete Solution Answers
$1,000(1+0.02)^5 = 1104 FV=R/i*[(1+i)^n-1]=2500/0.05*(1.05^5-1)=13814.08 R=PV*i/(1-1/(1+i)^n)=2000...
Related Solutions
Comments
Posted by: Fibermet
Fibermet
Senior JournalistBudget: $20
Ready
Tags: Business
Ethnography
Sell Your Solution Report Solution Support Center
Online Users
-
Fibermet
Today
A+ - Thank you!
Thanks for the positive feedback!