BMIS330 LAB 18 Complete Solution

LAB 18 ANSWER TEMPLATE

Problem 1:
IP address:  192.168.10.0 /27 (given)    
a.    Subnet Mask: 255.255.255.224
b.    Bits Borrowed: 3
c.    Number of subnets: 8      
d.    Magic number: 32  
e.    Number of valid hosts per subnet: 30
f.    (Sub) network address of subnet 0: 192.168.10.0
g.    First usable host address in subnet 0: 192.168.10.1  
h.    Last usable host address in subnet 0: 192.168.10.30   
i.    Broadcast address in subnet 0: 192.168.10.31
j.    (Sub) Network address in subnet 3: 192.168.10.64
k.    Last usable host address in subnet 4: 192.168.10.158

Subnet    Subnet address    1st Host address    Last Host address    Broadcast
0    192.168.10.0    192.168.10.1    192.168.10.30    192.168.10.31
1    192.168.10.32    192.168.10.33    192.168.10.62    192.168.10.63
2    192.168.10.64    192.168.10.65    192.168.10.94    192.168.10.95
3    192.168.10.96    192.168.10.97    192.168.10.126    192.168.10.127
4    192.168.10.128    192.168.10.129    192.168.10.158    192.168.10.159
5    192.168.10.160    192.168.10.161    192.168.10.190    192.168.10.191
6    192.168.10.192    192.168.10.193    192.168.10.222    192.168.10.223
7    192.168.10.224    192.168.10.225    192.168.10.254    192.168.10.255

Problem 2:
IP address: 192.168.10.0 / 26 (given)
a.    Subnet Mask: ____255.255.255.192_____________________________________
b.    Bits Borrowed: ________2_________________________________
c.    Number of subnets: _______4__________________________________    
d.    Magic number: _____________64____________________________
e.    Number of valid hosts per subnet: ___62______________________________________
f.    (Sub) network address of subnet 0: _____192.168.10.0_____________
g.    First usable host address in subnet 0: _____192.168.10.1_____________
h.    Last usable host address in subnet 0: ______192.168.10.62
i.    Broadcast address in subnet 0: ____________192.168.10.63________________
j.    (Sub) Network address in subnet 1: _________192.168.10.64_________________
k.    Last usable host address in subnet 2: __________192.168.10.190____________

Subnet    Subnet address    1st Host address    Last Host address    Broadcast
0    192.168.10.0    192.168.10.1    192.168.10.62    192.168.10.63
1    192.168.10.64    192.168.10.65    192.168.10.126    192.168.10.127
2    192.168.10.128    192.168.10.129    192.168.10.190    192.168.10.128
3    192.168.10.192    192.168.10.193    192.168.10.254    192.168.10.255
Etc.    192.168.10.256    192.168.10.257    192.168.10.318    192.168.10.319
                
                

Problem 3:
IP address: 192.168.10.0 (given)
Subnet Mask: 255.255.255.240
a.    Slash prefix: _____/28____________________________________
b.    Bits Borrowed: ___________4_____________________________
c.    Number of possible subnets: _____16____________________________________    
d.    Magic number: ___________16______________________________
e.    Number of usable hosts per subnet: _____14____________________________________
f.    (Sub) network address of subnet 0: ______192.168.10.0_________________________
g.    First usable host address in subnet 0: _____192.168.10.1______________________
h.    Last usable host address in subnet 0: ______192.168.10.14__________________
i.    Broadcast address in subnet 0: ___________192.168.10.15___________
j.    (Sub) Network address in subnet 1: ________192.168.10.16___
k.    Last usable host address in subnet 2: _______192.168.10.46___________

Subnet    Subnet address    1st Host address    Last Host address    Broadcast
0    192.168.10.0    192.168.10.1    192.168.10.14    192.168.10.15
1    192.168.10.16    192.168.10.17    192.168.10.30    192.168.10.31
2    192.168.10.32    192.168.10.33    192.168.10.46    192.168.10.47
3    192.168.10.48    192.168.10.49    192.168.10.62    192.168.10.63
Etc.    192.168.10.64    192.168.10.65    192.168.10.78    192.168.10.79
                
                

Problem 4:
IP address: 192.168.10.0 (given)
Minimum number of subnets needed: 31
a.    Slash prefix: _________________________________________
b.    Subnet Mask: _________________________________________
c.    Bits Borrowed: _________________________________________
d.    Number of possible subnets: _________________________________________    
e.    Magic number: _________________________________________
f.    Number of valid hosts per subnet: _________________________________________
g.    (Sub) network address of subnet 0: _________________________________________
h.    First usable host address in subnet 0: _________________________________________
i.    Last usable host address in subnet 0: _________________________________________
j.    Broadcast address in subnet 0: _________________________________________
k.    (Sub) Network address in subnet 1: _________________________________________
l.    Last usable host address in subnet 2: _________________________________________

Subnet    Subnet address    1st Host address    Last Host address    Broadcast
0                
1                
2                
3                
Etc.                
                

Problem 5:    
IP address: 192.10.10.0 (given) (Note that this address is slightly different than above)
Minimum number of hosts needed per subnet: 16
(Remember that the goal is to find a solution that will waste as few host addresses as possible but still satisfy the requirements.)
a.    Slash prefix: _________________________________________
b.    Subnet Mask: _________________________________________
c.    Bits Borrowed: _________________________________________
d.    Number of possible subnets: _________________________________________    
e.    Magic number: _________________________________________
f.    Number of valid hosts per subnet: _________________________________________
g.    (Sub) network address of subnet 0: _________________________________________
h.    First usable host address in subnet 0: _________________________________________
i.    Last usable host address in subnet 0: _________________________________________
j.    Broadcast address in subnet 0: _________________________________________
k.    (Sub) Network address in subnet 1: _________________________________________
l.    Last usable host address in subnet 2: _________________________________________

Subnet    Subnet address    1st Host address    Last Host address    Broadcast
0                
1                
2                
3                
Etc.                
                
Answer the following questions. Try to answer them without using tables to guide you:
1.    How many usable hosts per sub-network will you have using a /20 address? ______
2.    Given a Class B address, what is the magic number if you need to subnet using a /23 prefix? ______________________
3.    In a Class B address, how many sub-networks can you have with a /18 prefix? _______________
4.    How many total addresses per network can you have with a subnet mask of 255.255.224.0? (Note that total addresses include network and broadcast addresses.)___________

BMIS330 LAB 18 Complete Solution

• BMIS 330 LAB 18 Solution.docx 491 KB

Pay only $20.00

Rating: A+ Purchased: 11 x Posted By: Vikas

• «
• 1
• 2
• 3
• »

A+ - Thank you!

Vikas

Thanks for the positive feedback!